Answer
0.113 M
Explanation
Given that:
The volume of the stock solution, V₁ = 50.0 mL
The concentration of the stock solution, C₁ = 1.74 M
The volume of the solution the chemist made, V₂ = 770.0 mL
What to find:
The concentration (C₂) of the BaCl₂ solution the chemist made.
Step-by-step solution:
The concentration (C₂) of the chemist's working solution can be calculated using the dilution formula below:
[tex]\begin{gathered} C_1V_1=C_2V_2 \\ \\ C_2=\frac{C_1V_1}{V_2}=\frac{1.74M\times50.0mL}{770.0mL} \\ \\ C_2=\frac{87M}{770.0} \\ \\ C_2=0.113M \end{gathered}[/tex]Hence, the concentration of the chemist's working solution is 0.113 M.
