Respuesta :
Answer:
[tex]3Ba^{2+}\text{ + 6Cl}^-\text{ }\rightarrow\text{ 3BaCl}_{2(s)}[/tex]Explanation:
Here, we want to write the net ionic equation
We start by writing the complete equation of reaction:
[tex]2CrCl_3\text{ + 3Ba\lparen NO}_3)\placeholder{⬚}_2\rightarrow3BaCl_{2(s)}\text{ + 2Cr\lparen NO}_3)\placeholder{⬚}_3[/tex]Now, we write out the ions as follows:
[tex]2Cr^{3+}\text{ + 6Cl}^-\text{ + 3Ba}^{2+}\text{ + 3NO}_3^-\text{ }\rightarrow\text{ 3BaCl}_2\text{ + 2Cr}^{3+}\text{ + 3NO}_3^-[/tex]The Chromium and Nitrate ions are spectator ions
Thus, we have:
[tex]3Ba^{2+}\text{ + 6Cl}^-\text{ }\rightarrow\text{ 3BaCl}_2[/tex]