Respuesta :

Solution

For this case we can do the following:

[tex]\frac{\frac{2}{x}-\frac{4}{y}}{-\frac{5}{y}+\frac{3}{x}}[/tex]

We can start with the numerator and we have:

[tex]\frac{2}{x}-\frac{4}{y}=\frac{2y-4x}{xy}=\frac{2(y-2x)}{xy}[/tex]

For the denominator we have:

[tex]-\frac{5}{y}+\frac{3}{x}=\frac{3y-5x}{xy}[/tex]

And replacing we got:

[tex]\frac{\frac{2(y-2x)}{xy}}{\frac{3y-5x}{xy}}=\frac{2(y-2x)}{3y-5x}[/tex]

Then the correct answer would be:

[tex]\frac{2(y-2x)}{3y-5x}[/tex]