Input x Output y3. -56. -49. -3What is a equation

The above notation gives us the output ( y ) which is a function of input variable ( x ). This means that whatever relationship these two variables have the value of output ( y ) is related to the imput variable ( x ).

We are given a table/list of values of output ( y ) corresponding to each value of input variable ( x ) as follows:

Input ( x ) Output ( y )

3 -5

6 -4

9 -3

There are a series of steps that we must take to arrive at the equation that relates two variables.

Step 1: Determine the type of relationship between two variables by intuition

The first step in the process is the hardest of all. We have to critically analyze each input value ( x ) and its corresponding output value ( y ) with successive pair of values.

There are many types of relationships possible ( polynomial order, exponential, logarithmic, trigonometric, radical, etc .. ).

We can conjure up a way by comparing outputs of successive values to determine the type of relationship possible.

So looking at the first value:

[tex]y\text{ = f ( 3 ) = -5}[/tex]

The successive value:

[tex]y\text{ = f ( 6 ) = -4}[/tex]

The next successive value:

[tex]y\text{ = f ( 9 ) = -3}[/tex]

Here if scrutinize between each successive value of input variable ( x ) we see that there is a "3 unit step-up" in each pair of values i.e ( 3 -> 6 -> 9 ).

Next we compare each output values ( y ) for successive pairs. We see that with every step increase of 3 units in ( x ) value there is an increase of ( 1 ) unit in output value i.e ( -5 -> -4 -> -3 ).

Conclusion: Combing the result of above analysis we see that with each 3 step increase in input value ( x ) there is an increase in output value ( y ) by 1 unit.

This gives us the idea that the two variables are linearly related to one another.

Therefore, the type of relationship is:

[tex]\text{straight line }\text{ }[/tex]

Step 2: Recall the equation for the type of relationship between two vairbales x and y

Once we have determined the type of relationship between two variables. We will have to resort to our equation bank and pluck out the corresponding equation that expresses a LINEAR relationship i.e equation of a straight line.

The slope-intercept form of a straight line is:

[tex]y\text{ = m}\cdot x\text{ + c}[/tex]

Step 3: Determine the complete equation of function by defining the arbitrary constants.

The above equation is valid for all straight lines that express a linear relationship. However, we seek to find a unique straight line for the given set of points.

Every unique straight line equation would have either of the constants different. The constants defined in a striaght line equation are:

[tex]\begin{gathered} m\colon\text{ The slope( gradient ) of the line} \\ c\colon\text{ The y-intercept} \end{gathered}[/tex]

To determine these constants we will use the given pairs of coordinates of input and output variables, x and y respectively.

To determine the slope (m) of an equation:

[tex]m\text{ = }\frac{y_2-y_1}{x_2-x_1}[/tex]

The above expression relates the change in output value ( y ) with respect to change in input variable ( x ).

To determine the constant ( m ) we will use the conclusion from Step 1:

"3 step increase in input of ( x ) value there is an increase in output value ( y ) by 1 unit."

Therefore,

[tex]m\text{ = }\frac{+1}{+3}\text{ = }\frac{1}{3}[/tex]

To determine the value of y-intercept ( c ). We will plug in the value of ( m ) into the general equation of a straight line written in step 2:

[tex]y\text{ = }\frac{1}{3}x\text{ + c}[/tex]

Now, we will use any pair of input and output value.

[tex]x\text{ = 3 , y = -5}[/tex]

Substitute the pair of values into the derived equation expressed above and solve for constant ( c ):

[tex]\begin{gathered} -5\text{ = }\frac{1}{3}\cdot(3)\text{ + c} \\ -5\text{ = 1 + c} \\ c\text{ = -6} \end{gathered}[/tex]

Note: The above step implies that following equation must satisfy each and every data pair of point given to us ( table ). Or each and every value must lie on the line. For that each value must satisfy the equation of line.

Step 4: Write the complete equation of the relationship

Once we have evaluated the values of equation defining constants ( m and c ). We can simply plug in the values into the general equation relationship ( Linear - slope intercept form ) as follows:

[tex]m\text{ = }\frac{1}{3}\text{ , c = -6}[/tex]

Therefore, the equation for the set of values given to us is:

[tex]\begin{gathered} \textcolor{#FF7968}{y}\text{\textcolor{#FF7968}{ = }}\textcolor{#FF7968}{\frac{1}{3}\cdot x}\text{\textcolor{#FF7968}{ - 6}} \\ OR \\ y\text{ = }\frac{x\text{ - 18}}{3} \\ \textcolor{#FF7968}{3y}\text{\textcolor{#FF7968}{ = x - 18}} \end{gathered}[/tex]