Step 1:
Write the equation
A(n) = 3 + (n - 1)5
Step 2:
To find A(2)
Compare A(2) with A(n)
You can see that n = 2 for A(2)
Next, substitute n = 2 in A(n) = 3 + (n-1)5 to find A(2)
[tex]\begin{gathered} A(n)\text{ = 3 + (n - 1)5} \\ A(2)\text{ = 3 + (2 - 1) }\times\text{ 5} \\ A(2)\text{ = 3 + 1}\times5 \\ A(2)\text{ = 3 + 5} \\ A(2)\text{ = 8} \end{gathered}[/tex]Step 3
Let find A(4)
[tex]\begin{gathered} A(n)\text{ = 3 + (n - 1)5} \\ \text{From A(4), n = 4} \\ A(4)\text{ = 3 + ( 4 - 1 ) }\times\text{ 5} \\ A(4)\text{ = 3 + 3}\times5 \\ A(4)\text{ = 3 + 15} \\ A(4)\text{ = 18} \end{gathered}[/tex]Final answer
A(4) = 18
