A stick 1 meter long casts a shadow 0.7 meters long,
A building casts a shadow 22 meters long.
According to the given statement,
Since the both the angle θ are equal because they are form in the same source if light
From the property of similar triangle;
If one of the acute angles of a right triangle is congruent to an acute angle of another right triangle, then by Angle-Angle Similarity the triangles are similar.
So, triangleAOB is similar to triangle PQR
Now, from the property of similar triangle;
The SAS rule states that two triangles are similar if the ratio of their corresponding two sides is equal.
Thus,
[tex]\frac{AO}{PQ}=\frac{OB}{QR}=\frac{BA}{RP}[/tex]Substitute the value of the side; as,
OB = 1, AO = 0.7m
PQ = 22, QR
[tex]\begin{gathered} \frac{AO}{PQ}=\frac{OB}{QR}=\frac{BA}{RP} \\ \frac{0.7}{22}=\frac{1}{QR} \\ \text{Apply cross multiplication;} \\ 0.7QR=\text{ 1}\times22 \\ QR=\frac{22}{0.7} \\ QR=\text{ 31.42 m} \end{gathered}[/tex]So, the height of the building , QR = 31.42 m
Answer : 31.42 m
..........
