After I rewrite the fraction how do I get it to be less than one on the fractional part (Question 6)

The question is given to be:
[tex]8\frac{4}{12}+3\frac{6}{12}[/tex]Step 1: Add up the whole number parts
[tex]8+3=11[/tex]Step 2: Add up the fraction parts
[tex]\frac{4}{12}+\frac{6}{12}=\frac{10}{12}[/tex]Step 3: Combine the two calculated parts. This means that the result looks like this:
[tex]\Rightarrow11\frac{10}{12}[/tex]Hence, the answer is:
[tex]8\frac{4}{12}+3\frac{6}{12}=11\frac{10}{12}[/tex]