Respuesta :
Answer:
The slope of line B = 5/7
Explanations:Line A passes through the points (1, 10) and (6, 3)
The slope of a line passing though the points (x₁, y₁) and (x₂, y₂) is given by the formula:
[tex]m\text{ = }\frac{y_2-y_1}{x_2-x_1}[/tex][tex]\begin{gathered} \text{Let the slope of the line A passing thorugh the points (1,10) and (6,3) be m}_A \\ _{} \end{gathered}[/tex][tex]\begin{gathered} m_A=\text{ }\frac{3-10}{6-1} \\ m_A=\text{ }\frac{-7}{5} \end{gathered}[/tex]When two lines are perpendicular, the slope of one is the negative inverse of the other.
Since line B is perpendicular to line A:
[tex]\begin{gathered} m_B=\text{ }\frac{-1}{m_A} \\ m_B=\text{ -1 }\div\text{ }\frac{-7}{5} \\ m_B=\text{ -1 }\times\frac{-5}{7} \\ m_B=\text{ }\frac{5}{7} \end{gathered}[/tex]The slope of line B = 5/7
