Step 1: Express the statement: a fourth of 10 centimeters mathematically
[tex]\frac{1}{4}\times10\operatorname{cm}\Rightarrow\frac{10}{4}cm\Rightarrow2.5\operatorname{cm}[/tex]Step 2: Write the map distance equivalence
[tex]\text{2}.5\operatorname{cm}=150m\text{ on map}[/tex]Step 3: The distance on the map from Springfield to Oakwood is 1.5 of 10 centimeters, this can be expressed as;
[tex]\begin{gathered} 1.5\text{ of 10cm} \\ \frac{3}{2}\times10\operatorname{cm}=\frac{30}{2}cm=15\operatorname{cm} \end{gathered}[/tex]
Step 4: find the distance in meters from Springfield to Oakwood
[tex]\begin{gathered} 2.5\operatorname{cm}=150m \\ 1\operatorname{cm}=xm \\ xm=\frac{150m\times1\operatorname{cm}}{2.5\operatorname{cm}} \\ xm=60m \\ 1\operatorname{cm}=60m \end{gathered}[/tex][tex]\begin{gathered} \text{The distance on map will be} \\ 15\times60=900m \end{gathered}[/tex]Hence, the distance in meters from Springfield to Oakwood is 900meters
