A 56 kg student stands on top of a spring in an elevator accelerating upward at 3.5 m/s2m/s2. The spring constant is 2900 N/mN/m. Part A By how much is the spring compressed

Respuesta :

Given data,

Mass,

[tex]m=56\text{ kg}[/tex]

Acceleration,

[tex]a=3.5m/s^2[/tex]

Spring constant,

[tex]k=2900\text{ N/m}[/tex]

Given acceleration is upward, hence

[tex]\begin{gathered} (g+a)=9.8m/s^2+3.5m/s^2 \\ (g+a)=13.3m/s^2 \end{gathered}[/tex]

Consider the equation of force,

[tex]\begin{gathered} F=kx \\ m(g+a)=kx \\ x=\frac{m(g+a)}{k} \end{gathered}[/tex]

Substitute the given and calculated values.

[tex]\begin{gathered} x=\frac{56\text{ kg}\times13.3m/s^2}{2900\text{ N/m}} \\ x=25.6\text{ cm} \end{gathered}[/tex]

Hence, the spring compressed is 25.6 cm.