Explanation
The binomial probability distribution formula is given as
[tex]P(x)=\frac{n!}{(n-x)!x!}p^xq^{n-x}[/tex]
From the question, we have that n=6, x =1 and p =0.3. Hence, q = 1-p =0.7
Therefore, we will have that
[tex]\begin{gathered} P(1)=\frac{6!}{(6-1)!1!}(0.3)^1(0.7)^{6-1} \\ P(1)=\frac{6!}{5!1!}(0.3)(0.7)^5 \\ =\frac{6\times5!}{5!\times1}(0.3)(0.7)^5 \\ =6(0.3)(0.7)^5 \\ =0.3\times\:1.00842 \\ =0.3025 \end{gathered}[/tex]
Answer: 0.3025
