The sample volume of propane, a component of lp gas at STP, is 37.12L.
The combined gas law combines the principles of Gay-Lussac, Boyle, and Charles.
According to the combined gas equation, P1×V1/T1 = P2×V2/T2
Assuming the gas is an ideal gas will help us solve this problem. We can then apply the combined gas equation, P1×V1/T1 = P2×V2/T2.
Where,
P1 = initial pressure of the gas = 922 torr = 1.213 atm
P2 = final pressure of the gas at STP = 1 atm
V1 = initial volume of the gas = 35.3 L
V2 = at STP final volume of the gas =?
T1 = initial temperature of the gas = 315 K
T2 = final temperature of the gas at STP = 273 K
By using the following equation and putting the given values, we obtain:
P1×V1/T1 = P2×V2/T2
Hence, V2 = P1×V1×T2 / T1×P2
V2 = 1.213×35.3×273 / 315×760
Therefore, the volume of the gas at STP is, 37.12 L
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