In ABCD, the measure of ZD=90°, BD = 12, DC = 35, and CB = 37. What ratiorepresents the sine of ZC?

Draw a diagram to visualize the triangle:
The sine of an angle in a right triangle is defined as the quotient between the side opposite to that angle and the hypotenuse.
The side opposite to the angle C is BD, and the hypotenuse of the triangle is CB. Then:
[tex]\sin (\angle C)=\frac{BD}{CB}[/tex]Substitute the lengths of BD and CB to find the ratio that represents the sine of the angle C in this case:
[tex]\sin (\angle C)=\frac{12}{37}[/tex]Therefore, the answer is:
[tex]\frac{12}{37}[/tex]