Given:
[tex]\begin{gathered} a(q)=q^2+7q+12inches^2\text{ (Area of rectangle)} \\ \text{width =(q + 3) inches} \end{gathered}[/tex]Required: length?
the formula for the area of a rectangle :
[tex]\text{Area of rectangle = length }\times\text{ width}[/tex]let the length of the rectangle be l
[tex]\begin{gathered} q^2\text{ + 7q + 12 = (q + 3) }\times\text{ l} \\ l\text{ = }\frac{q^2\text{ + 7q + 12}}{q\text{ + 3}} \end{gathered}[/tex]Using the long division method
[tex]l\text{ = (q + 4) inches}[/tex]
