Given:
The distance-time equation is given below as
[tex]\begin{gathered} d=0.15t \\ \text{where,} \\ d=\text{distance(miles)} \\ t=\text{time(seconds)} \end{gathered}[/tex]From the question,
The time given is
[tex]t=30\text{ seconds}[/tex]Concept:
Substitute the value of t=30 sec in the distance-time equation given
By substituting the value of t=30 , we will have
[tex]\begin{gathered} d=0.15t \\ d=0.15\times30 \\ d=4.5\text{ miles} \end{gathered}[/tex]Hence,
The distance the airplane will travel in 30 seconds = 4.5 miles
