Given:
The equation is:
[tex]\begin{gathered} y=11x^2 \\ y=x^2+4 \end{gathered}[/tex]Required:
Find the area enclosed by the region.
Explanation:
The given equation is:
[tex]\begin{gathered} y=11x^2 \\ y=x^2+4 \end{gathered}[/tex]Find the intersecting point of the curve.
[tex]\begin{gathered} 11x^2=x^2+4 \\ 10x^2=4 \\ x^2=\frac{4}{5} \\ x=\pm\sqrt{\frac{4}{5}} \\ x=\pm\frac{2}{\sqrt{5}} \end{gathered}[/tex]The enclosed area is:
[tex][/tex]