Given:
The ratio of the diagonals of the squares ABCD and DEFG is:
[tex]AC:FD=7:5[/tex]
Required-the value of CE.
Explanation:
Given that the ratio of the diagonals of the squares ABCD and DEFG is:
[tex]AC:FD=7:5[/tex]
So, the sides will be in the same ratio.
[tex]AD:GD=7:5[/tex]
Let the sides of the two triangles ABCD and DEFG be 7x and 5x.
Given that
[tex]AG=3cm[/tex]
So, we can write AG as:
[tex]\begin{gathered} AG=AD-GD \\ 3=7x-5x \\ \\ 2x=3....(1) \end{gathered}[/tex]
Now, we have to find CE, so we can write CE as:
[tex]\begin{gathered} CE=CD+DE \\ \\ CE=7x+5x \\ \\ CE=12x \\ \\ CE=6(2x) \\ \\ CE=6\times3 \\ \\ CE=18cm \end{gathered}[/tex]
Final answer: The value of CE is 18 cm.
