The Solution.
The triangle to be drawn must be a right-angled triangle since it is link with trigonometric ratios. So, below is the right-angled triangle:
By Trigonometrical Ratios,
[tex]\sin A=\frac{opposite}{\text{Hypotenuse}}=\frac{6}{10}=\frac{3}{5}\text{ or 0.6}[/tex]
Similarly,
[tex]\cos A=\frac{\text{Adjacent}}{\text{Hypotenuse}}=\frac{8}{10}=\frac{4}{5}\text{ or 0}.8[/tex]
Also, by Trigonometrical Ratio,
[tex]\tan A=\frac{\text{opposite}}{\text{Adjacent}}=\frac{6}{8}=\frac{3}{4}\text{ or 0}.75[/tex]
