Given
Triangle ABC
with vertices A(-9,4), B(-4,5), C(-7,9)
find the Area
Procedure
[tex]\begin{gathered} A=|\frac{-9(5-9)+(-4)(9-4)+(-7)(4-5)}{2}| \\ A=|\frac{(-9)(-4)+(-4)(5)+(-7)(-1)}{2}| \\ A=|\frac{36+(-20)+7}{2}| \\ A=|\frac{23}{2}| \\ A=11.5 \end{gathered}[/tex]
The answer is: the area is 11.5 units^2
