Given two points coordinate
[tex](2,-4)\text{ and (-3,-3)}[/tex]The equation of the line in slope-intercept form can be obtained using
[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]Define the x and y values, then substitute in the above formula
[tex]x_1=2,y_1=-4,x_2=-3,y_2=-3[/tex][tex]\begin{gathered} y-(-4)=\frac{-3-(-4)}{-3-2}(x-2) \\ y+4=\frac{-3+4}{-5}(x-2) \\ y+4=-\frac{1}{5}(x-2) \end{gathered}[/tex][tex]\begin{gathered} y+4=-\frac{1}{5}x+\frac{2}{5} \\ y=-\frac{1}{5}x+\frac{2}{5}-4 \\ y=-\frac{1}{5}x-\frac{18}{5} \end{gathered}[/tex]Hence, Option C is the correct answer
