30 liters of 50% solution and 30 liters of 70% solution.
1) We can solve this problem, making use of an equation.
x- the amount of 70%
60 -x stands for the amount of 50% solution. From this we can write the following equation, rewriting the percentages as decimal numbers:
[tex]\begin{gathered} 0.5(60-x)+0.7x=0.6(60) \\ 30-0.5x+0.7x=36 \\ 0.2x=36-30 \\ 0.2x=6 \\ \frac{0.2x}{0.2}=\frac{6}{0.2} \\ x=30 \end{gathered}[/tex]Note that we equated two equations, the first one:
[tex]0.5(60-x)+0.7x[/tex]provides the amount of 50% solution minus that 60L and the second one yields 60% of those 60 Liters, so with x, we get the remaining amount of that 50% solution.
b) Since the other question refers to the amount of of the 70% solution and we also know that Gabe needs 30 liters of the 50% solution we can write the following, calling the second amount as y:
[tex]\begin{gathered} 30+y=60 \\ y=60-30 \\ y=30 \end{gathered}[/tex]Note the total of 60 Liters
2) Thus the answer is 30 liters of 50% solution and 30 liters of 70% solution.