Tory and her friend Terrence ride their bikes to school each day. On one particular day. Tory started out 5 minutes before Terrence. Tory rides atteot 30 feet perrides at a rate of 1.056 feet per minuteHow long had. Tory been riding when Terrence caught up with her?

Question

25-10-2022
Mathematics

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Tory and her friend Terrence ride their bikes to school each day. On one particular day. Tory started out 5 minutes before Terrence. Tory rides atteot 30 feet perrides at a rate of 1.056 feet per minuteHow long had. Tory been riding when Terrence caught up with her?

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HylaV308355 HylaV308355 · Answer 1 · 2022-10-25T22:48:28+02:00

Answer:

30 minutes

Explanation:

The expression that give us the distance that Tory has ride after t minutes is:

D = 880t

Because Tory rides at 880 feet per minute.

At the same way, the distance that Terrence has ride after t minutes is equal to:

D = 1056(t - 5)

Because Terrence rides at 1056 feet per minute and he starts out 5 minutes after Tory

Now, we need to find t when both expressions are equal, so we can formulate the following equation:

[tex]880t=1056(t-5)[/tex]

So, solving for t, we get:

[tex]\begin{gathered} 880t=1056t-1056\cdot5 \\ 880t=1056t-5280 \\ 880t-1056t=-5280 \\ -176t=-5280 \\ t=\frac{-5280}{-176} \\ t=30 \end{gathered}[/tex]

Therefore, the answer is 30 minutes