a projectile is thrown so that it's distance above the ground after t seconds is h(t)=-16t^2+660t. after how many seconds does it reach its maximum height

Respuesta :

The function is given to be:

[tex]h(t)=-16t^2+660t[/tex]

The vertex of the parabola represents the highest (or lowest) point of a parabola. Given the normal form of a quadratic formula:

[tex]f(x)=ax^2+bx+c[/tex]

the vertex is calculated to be:

[tex]x=-\frac{b}{2a}[/tex]

From the function of the projectile given, we have:

[tex]\begin{gathered} a=-16 \\ b=660 \end{gathered}[/tex]

Therefore, the vertex is:

[tex]t=-\frac{660}{2\times(-16)}=\frac{660}{32}=20.625[/tex]

This can be confirmed by graphing the function:

Therefore, the time taken is 20.625 seconds.

Ver imagen MyP558261