y= -3x+2
slope A = -3
Slope B = 1/3
Perpendicular lines
1) Rewriting each equation in the slope-intercept form i.e.
y=mx+b
[tex]\begin{gathered} y=\frac{1}{3}x+4 \\ 3x+y=2\Rightarrow y=-3x+2 \\ \mleft\{\begin{aligned}y=\frac{1}{3}x+4 \\ y=-3x+2\end{aligned}\mright. \end{gathered}[/tex]2) The slope, as it is written in the slope-intercept form is the coefficient that comes along the x, so the slope for A is
[tex]\begin{gathered} \text{slope for A =}\frac{1}{3} \\ \text{slope for B= -3} \end{gathered}[/tex]3)We have the following rules to determine two lines position:
Parallel lines same slope
Perpendicular lines: reciprocal and opposite lines
For example -3 and 1/3
