Solution:
Given the equation;
[tex](t+2)^2=36[/tex]
Step 1: Take square root of both sides;
[tex]\begin{gathered} \sqrt{(t+2)^2}=\sqrt{36} \\ \\ t+2=\pm6 \end{gathered}[/tex]
Step 2: Subtract 2 from both sides;
[tex]\begin{gathered} t+2-2=-2\pm6 \\ \\ t=-2\pm6 \end{gathered}[/tex]
Step 3: Separate the answers;
[tex]\begin{gathered} t=-2-6,t=-2+6 \\ \\ t=-8,t=4 \end{gathered}[/tex]
ANSWER:
[tex]t=-8, t=4[/tex]
