Find mZABD and mZCBD given mZABC =111°A(-10x + 58)(6x + 41)BmZABD =and mZCBD =

Given;
[tex]\begin{gathered} m\angle ABD=(-10x+58)^0 \\ m\angle CBD=(6x+41)^0 \\ m\angle ABC=111^0 \end{gathered}[/tex]From the given diagram;
[tex]m\angle ABD+m\angle CBD=m\angle ABC[/tex]substituting the given;
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