A stone is thrown vertically up from the ground. It reaches a maximum height of 150 m in 5 seconds. Determine the velocity with which the stone is thrown upward.

Respuesta :

Given:

Maximum height = 150 m

Time it takes to reach naximum height = 5 seconds.

Let's find the velocity with which the stone is thrown upward.

To find the velocity, apply the formula:

[tex]x=ut+\frac{1}{2}at^2[/tex]

Where:

• u is the initial velocity (velocity with which the stone is thrown upward)

,

• a is acceleration due to gravity = 9.8 m/s²

,

• x is the maximum height = 150 m

,

• t is the time.

At the maximum height, the final velocity is 0 m/s.

Thus, we have:

[tex]150=5u+\frac{1}{2}\times9.8\times5^2[/tex]

Let's solve for u.

We have:

[tex]\begin{gathered} 150=5u+4.9\times25 \\ \\ 150=5u+122.5 \\ \\ 5u=150-122.5 \\ \\ 5u=27.5 \end{gathered}[/tex]

Divide both sides by 5:

[tex]\begin{gathered} \frac{5u}{5}=\frac{27.5}{5} \\ \\ u=5.5\text{ m/s} \end{gathered}[/tex]

Therefore, the velocity with which the stone is thrown upward is 5.5 m/s.

ANSWER:

5.5 m/s