Given:
Maximum height = 150 m
Time it takes to reach naximum height = 5 seconds.
Let's find the velocity with which the stone is thrown upward.
To find the velocity, apply the formula:
[tex]x=ut+\frac{1}{2}at^2[/tex]Where:
• u is the initial velocity (velocity with which the stone is thrown upward)
,• a is acceleration due to gravity = 9.8 m/s²
,• x is the maximum height = 150 m
,• t is the time.
At the maximum height, the final velocity is 0 m/s.
Thus, we have:
[tex]150=5u+\frac{1}{2}\times9.8\times5^2[/tex]Let's solve for u.
We have:
[tex]\begin{gathered} 150=5u+4.9\times25 \\ \\ 150=5u+122.5 \\ \\ 5u=150-122.5 \\ \\ 5u=27.5 \end{gathered}[/tex]Divide both sides by 5:
[tex]\begin{gathered} \frac{5u}{5}=\frac{27.5}{5} \\ \\ u=5.5\text{ m/s} \end{gathered}[/tex]Therefore, the velocity with which the stone is thrown upward is 5.5 m/s.
ANSWER:
5.5 m/s