What is the area of the sector of the circle below, if the radius is16 m. and the central angle < AOB measures 62°. (round answer to the nearest tenth)

To determine the area of the shaded sector, we use the formula below.
[tex]A=\frac{\theta}{360\degree}(\pi r^2)[/tex]Based on the question, the given information are:
• radius = 16 meters
,• central angle = 62°
,• pi value = 3.14159
Let's plug the given information into the formula above.
[tex]A=\frac{62}{360}(3.14159)(16m)^2[/tex]Then, solve.
[tex]A=0.17222(3.14159)(256m^2)[/tex][tex]A=138.509\approx138.5m^2[/tex]Therefore, the area of the shaded sector is approximately 138.5m². (Option C)