A chemist mixes 3.90 g of chlooform with 19.4 g of acetyl bromide And 83.4 g of heptane. Calculate the percent by mass of each component of the solution. Be sure each of your answer entries has the correct number of significant digits.

1) Define the equation for calculating mass percent.
[tex]\text{Percent by mass=}\frac{\text{mass of solute}}{\text{mass of solution}}\cdot100[/tex]2) The mass percent of chloroform
[tex]\text{Percent by mass of Chloroform=}\frac{3.90\text{ g of chloroform}}{3.90\text{ g + 19.4 g + 83.4 g }}\cdot100=\text{ 3.66\% chloroform}[/tex]The mass percent of chloroform is 3.66% chloroform.
3) The mass percent of acetyl bromide
[tex]\text{Percent by mass of acetyl bromide=}\frac{19.4\text{ g acetyl bromide}}{3.90g\text{ + 19.4g + 83.4g}}\cdot100=\text{ 18.2\%}[/tex]The mass percent of acetyl bromide is 18.2% acetyl bromide
4) The mass percent of heptane
[tex]\text{Percent by mass of heptane=}\frac{83.4g\text{ of heptane}}{3.90g\text{ +19.4g +83.4g}}\cdot100=\text{ 78.2\% of heptane}[/tex]The mass percent of heptane is 78.2% of heptane