The question requires us to calculate the rate of change of NO, given that the rate of change of Cl2 is -0.0500 M/s.
The balanced chemical reaction provided is:
[tex]2NO_{(g)_{}}+Cl_{2(g)}\to2NOCl_{(g)}_{}[/tex]From the stochiometry of the reaction we can say that Δ[NO] = 2/1 Δ[Cl2], thus we can calculate the rate of change of NO as:
[tex]\Delta\lbrack NO\rbrack=2\Delta\lbrack Cl_2\rbrack\to\Delta\lbrack NO\rbrack=2\times(-0.0500M/s)=-0.100M/s[/tex]Therefore, the rate of change of NO is -0.100 M/s.
