Can you help me find the slope, y-intercept, and the equation based off this chart?

y-interceptis As given by the question
There are given that the value of x and y.
Now,
For finding the value of the slope, choose two-point from the given table
So,
Suppose the two points are:
[tex](1,\text{ 5) and (}3,\text{ 3)}[/tex]Now,
From the formula of slope:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Where,
[tex]x_1=1,y_1=5,x_2=3,y_2=3[/tex]Put all the above value into the given formula
So,
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{3_{}-5_{}}{3_{}-1_{}} \\ m=-\frac{2}{2} \\ m=-1 \end{gathered}[/tex]Hence, the value of the slope is -1.
Now,
For the equation of the line that is based on the given chart, use two supposes point and the given slope.
So,
The two poin and slope is:
[tex](1,\text{ 5) and (3, 3) and m=-1}[/tex]Then,
From the formula of two point form;
[tex](y-y_1)=m(x-x_1)[/tex]Where,
[tex]x_1=1,y_1=5,x_2=3,y_2=3,\text{ m=-1}[/tex]Then,
Put all the given value into the above formula
So,
[tex]\begin{gathered} (y-y_1)=m(x-x_1) \\ (y-5_{})=-1(x-1_{}) \\ (y-5)=-x+1 \\ y-5+x-1=0 \\ y+x-6=0 \end{gathered}[/tex]Hence, the equation of the line is:
[tex]y=-x+6[/tex]Now,
To find the y-intercept, put x=0 and solve for x
So,
The y intercept of the given equation is:
[tex]\begin{gathered} y=-x+6 \\ y=-(0)+6 \\ y=6 \end{gathered}[/tex]Hence, the y-intercept is (0, 6)