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V The formula v= √ 2gh gives the velocity v, in feet per second, of an object after it falls h feet accelerated by gravity g, in feet per second squared. If g is approximately 32 feet per second squared, find how far an object has fallen if its velocity is 56 feet per second The object has fallen from its initial position.

Respuesta :

ANSWER:

49 ft

STEP-BY-STEP EXPLANATION:

Given:

g = 32 ft/m^2

v = 56 ft/s

Replacing:

[tex]\begin{gathered} 56=\sqrt[]{2\cdot32\cdot h} \\ 56=\sqrt[]{64h} \end{gathered}[/tex]

We solve for h which would be how far the object fell:

[tex]\begin{gathered} \sqrt{h}=\frac{56}{\sqrt[]{64}}=\frac{56}{8}=7 \\ h=7^2 \\ h=49 \end{gathered}[/tex]

The object was 49 feet high

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