The product of the next expression in the simplest radical form is:
[tex]\sqrt{6}\cdot10\cdot\sqrt{12}=\sqrt{6}\cdot10\cdot\sqrt{2^2\cdot3}=\sqrt{6}\cdot10\cdot2\cdot\sqrt{3}[/tex]Then
[tex]\sqrt{6}\cdot20\cdot\sqrt{3}=20\cdot\sqrt{6\cdot3}=20\cdot\sqrt{3^2\cdot2}=20\cdot3\cdot\sqrt{2}=60\cdot\sqrt{2}[/tex]Then, in the simplest radical form, the given expression can be rewritten as:
[tex]\sqrt{6}\cdot10\cdot\sqrt{12}=60\cdot\sqrt{2}[/tex]