The y-intercept is given by the value of y when x = 0, and the x-intercept is given by the value of x when y = 0.
The domain is all values of x the function can assume in order to y exist.
The axis of symmetry is the axis where the function is mirrowed.
a) y² = 8x -> y = √(8x)
[tex]\begin{gathered} \text{y-intercept:} \\ x=0\to y^2=0\to y=0 \\ \text{x-intercept:} \\ y=0\to x=0 \\ \text{Domain: all real numbers} \\ \text{Axis of symmetry: }x=0 \end{gathered}[/tex]
b) x² = 8y
[tex]\begin{gathered} \text{ y-intercept:} \\ x=0\to y=\frac{0}{8}=0 \\ \text{ x-intercept:} \\ y=0\to x^2=0\to x=0 \\ \text{Domain: all real numbers} \\ \text{Axis of symmetry: }x=0 \end{gathered}[/tex]
c) y² = -4x -> y = √(-4x)
[tex]\begin{gathered} \text{ y-intercept:} \\ x=0\to y^2=0\to y=0 \\ \text{ x-intercept:} \\ y=0\to x=0 \\ \text{Domain: }x\le0 \\ \text{Axis of symmetry: }y=0 \end{gathered}[/tex]
d) x² = -4y
[tex]\begin{gathered} \text{ y-intercept:} \\ x=0\to y=\frac{0}{-4}=0 \\ \text{ x-intercept:} \\ y=0\to x^2=0\to x=0 \\ \text{Domain: all real numbers} \\ \text{Axis of symmetry: }x=0 \end{gathered}[/tex]
