Answer:
[tex]\text{Area = 7.61 cm}^2[/tex]
Explanation:
Here, we want to find the area of triangle ABC
From what we have, we have two tangent lines coming from an external point
Mathematically, if we have two lines coming from an external point, with the two lines touching the circle at two different points, these two lines are of equal length
What this mean with respect to the situation on ground is that, AC and AB are of equal lengths
That means we have an isosceles triangle that could be re-drawn as:
Now, we proceed to get the area of the triangle
Mathematically, we have this as:
[tex]A\text{ = }\frac{1}{2}\times S^2\times\text{ }\sin \theta[/tex]
With respect to the given case, S is one of the sides marked while theta is the angle given
[tex]A\text{ = }\frac{1}{2}\times6^2\times\sin 25\text{ = }7.61cm^2[/tex]
