We have two bags:
- Bag A has 4 purple marbles and 16 green marbles.
- Bag B has 3 purple marbles and 9 green marbles.
If only one marble is picked, we can calculate the probability for each event.
Event 1: Choosing a purple marble from Bag B.
This has a probability of:
[tex]P(P_B)=\frac{3}{3+9}=\frac{3}{12}=0.25[/tex]Event 2: Choosing a purple or green marble from Bag A.
As all of the marbles from bag A are either purple or green, the probability of getting one of those colors is P = 1 (or 100%, total certainty).
Event 3: Choosing an orange marble from Bag B.
As there is no orange marbles in Bag B, there is no chance we pick a marble of this color. This event has a probability P = 0.
Event 4: Choosing a purple marble from Bag A.
There are 4 purple marbles out of 20 marbles in Bag A, so the probability is:
[tex]P(P_A)=\frac{4}{4+16}=\frac{4}{20}=0.2[/tex]Answer:
Then, we can order this events from least likely to most likely as:
Event 3
Event 4
Event 1
Event 2
