The sequence is;
[tex]64,32,16,\ldots[/tex]This is a geometric sequence of first term 64 and common difference 1/2,
Therefore, the nth term formula is;
[tex]\begin{gathered} T_n=ar^{n-1} \\ a=64\text{ and r=}\frac{1}{2} \\ T_n=64(\frac{1}{2})^{n-1} \end{gathered}[/tex]To obtain the fourth and fifth terms, we substitute n=4 and 5 into the equation;
[tex]\begin{gathered} T_4=64(\frac{1}{2})^3=8 \\ T_5=64(\frac{1}{2})^4=4 \end{gathered}[/tex]Therefore, the next terms of the sequence are 8 and 4.
