ANSWER
(1) 20 N*s
(2) 20 N*s
(3) 19.3 m/s
EXPLANATION
The impulse experienced by an object equals the change of momentum of the object. From the F-t graph, the change in momentum is the area under the curve. The curve shown is a trapezium, so the area is,
[tex]J=\Delta p=\frac{1}{2}h(B+b)=\frac{1}{2}\cdot50N\cdot(0.3+0.5)s=20N\cdot s[/tex]
The impulse or change in momentum of an object is given by,
[tex]\Delta p=m\cdot\Delta v=m\cdot(v_f-v_i)[/tex]
Solving for vf,
[tex]v_f=\frac{\Delta p}{m}+v_i[/tex]
The impulse, as found before, is 20N*s, the mass of the ball is 1.5kg and the initial velocity is 6m/s,
[tex]v_f=\frac{20N\cdot s}{1.5kg}+6m/s\approx19.3m/s[/tex]
