Respuesta :

Given:

[tex](x+5)^2+4(x+5)+12=0[/tex]

let u = x+5

so, the equation will become:

[tex]u^2+4u+12=0[/tex]

so, the equation is quadratic in form because the substitution u = x+5

The answer is the first statement

Note:

the second statement is wrong, because when the equation expanded, it will be a second degree polynomials not fourth degree

Also, the last 2 statements are wrong, because it is quadratic equation.

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