First, let's find the flow rate, it will be
[tex]Q=\frac{\Delta V}{\Delta t}[/tex]Where ΔV = 10*11*12, and Δt = 4 minutes, therefore
[tex]Q=\frac{\Delta V}{\Delta t}=\frac{10\cdot11\cdot12}{4}=\frac{1320}{4}=330\text{ ft}^3/\text{ min}[/tex]Now we can use the same definition and solve it for Δt
[tex]Δt=\frac{\Delta V}{Q}[/tex]But now we use the new volume and the previous flow rate
[tex]Δt=\frac{\Delta V}{Q}=\frac{30\cdot33\cdot35}{330}=105\text{ minutes}[/tex]Therefore it will take 105 minutes.
