The given quadratic function is
[tex]f(x)=(-x-1)^2+3[/tex]
It represented graphically by an upward parabola
Since the parabola is upward, then it has a minimum vertex
From the graph, the minimum vertex is (-1, 3)
Then let us answer the questions
Maximum point: None
Minimum point: (-1, 3)
To find f(-5), substitute x by 5 in the function above
[tex]\begin{gathered} f(-5)=(--5-1)^2+3 \\ f(-5)=(5-1)^2+3 \\ f(-5)=(4)^2+3 \\ f(-5)=16+3 \\ f(-5)=19 \end{gathered}[/tex]
To find f(6), substitute x by 6 in the function above
[tex]\begin{gathered} f(6)=(-6-1)^2+3 \\ f(6)=(-7)^2+3 \\ f(6)=49+3 \\ f(6)=52 \end{gathered}[/tex]
The answers:
f(-5) = 19
f(6) = 52
