This rectangle and right triangle have the same perimeter.What is the difference in their areas?A.0 square cmB.2.0 square cmC.3.6 square cmD.4.8 square cm

The area of the rectangle is
[tex]\begin{gathered} A_R=4\times3 \\ A_R=12\operatorname{cm} \end{gathered}[/tex]On the other hand, the area of the right triangle is
[tex]\begin{gathered} A_T=\frac{1}{2}(4.2)(4) \\ A_T=4.2\times2 \\ A_T=8.4\operatorname{cm} \end{gathered}[/tex]Then, the difference in their areas is
[tex]\begin{gathered} A_R-A_T=12-8.4_{} \\ A_R-A_T=3.6\operatorname{cm} \end{gathered}[/tex]so, the answer is option C.