SOLUTION
[tex]\begin{gathered} 12\text{ one dollar bills = 12 }\times1dollar=12\text{ }dollars \\ 4\text{ five-dollar bills = 4}\times5=20\text{ }dollars \\ 10\text{ quarters of dollar = 10}\times\frac{1}{4}=2.50\text{ dollars } \\ 12\text{ dimes = 12}\times0.1\text{ dollar = 1.20 dollars } \\ 40\text{ pennies = 0.40 dollars, then } \\ 132.51\text{ dollars } \\ 32.12\text{ dollars } \end{gathered}[/tex]Adding we have
[tex]12+20+2.50+1.20+0.40+132.51+32.12=200.73[/tex]But he wants to receive 2 twenty-dollar bills in cash, that is
[tex]2\times20\text{ dollars = 40 dollars }[/tex]So we will subtract from 200.73, we have
[tex]\begin{gathered} 200.73-40 \\ =160.73 \end{gathered}[/tex]Hence the answer is $160.73