What is the logarithmic form of the equation? Enter your answer by filling in the boxes.
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[tex]a^y=\text{ x}[/tex]
So then,
[tex]\log _a(x)=y_{}[/tex]
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In your case
[tex]2^a=\text{ 9 }[/tex]
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[tex]\log _2(9)=a_{}[/tex]
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Answer = a
