ABC is parallel to DEF and BE BF. Given that CBF = 45°, find the value of

Angle ABE and Angle CBF are congruent.
BE and BF are congruent, that makes the triangle isosceles.
Thus,
Angle ABE and Angle CBF are equal.
[tex]\angle\text{CBF}=\angle\text{ABE}=45\degree[/tex]