The sample space of rolling a dice is
S = {1,2,3,4,5,6}
The probability of rolling a 3, based on the sample space, is 1 out 6 chances
P(3) = 1/6
The probability of rolling an odd number, based on the sample space are {1,3,5}, is 3 out of 6 chances.
P(odd) = 3/6
By counting principle, the probability of showing a 3 on the first dice, and and odd number on second roll is
[tex]\begin{gathered} P(3\text{ then odd})=P(3)\cdot P(\text{odd}) \\ P(3\text{ then odd})=\frac{1}{6}\cdot\frac{3}{6} \\ P(3\text{ then odd})=\frac{3}{36} \\ P(3\text{ then odd})=0.083333\ldots \end{gathered}[/tex]Rounding to three decimal place, the probability is 0.083.
