Answer: We have to evaluate the cotangent for the given x and y coordinate points:
[tex]\begin{gathered} (x,y)=(\frac{\sqrt{3}}{4},-\frac{\sqrt{13}}{4}) \\ \\ x=\frac{\sqrt{3}}{4} \\ \\ y=-\frac{\sqrt{13}}{4} \end{gathered}[/tex]
The value of the cot function is:
[tex]\begin{gathered} cot(\theta)=\frac{x}{y} \\ \\ \therefore\rightarrow \\ \\ =\frac{\sqrt{3}}{4}\div-\frac{\sqrt{13}}{4}=-\frac{\sqrt{3}}{\sqrt{13}}=-\sqrt{\frac{3}{13}} \\ \\ =-\sqrt{\frac{3}{13}} \end{gathered}[/tex]
