Find the equation of the line passing through the points (3,-2) and (4,6)

The equation is of the form y = mx + b, where m is the slope and b is the y-intercept. Therefore:
- For m:
Given the points (3, -2) and (4, 6)
[tex]m=\frac{y2-y1}{x2-x1}=\frac{6-(-2)}{4-3}=\frac{6+2}{1}=\frac{8}{1}=8[/tex]- For b:
We use the point (4,6)
[tex]\begin{gathered} y=mx+b \\ 6=8(4)+b \\ 6=32+b \\ 6-32=32+b-32 \\ b=-26 \end{gathered}[/tex]Substitute the values, so the equation is:
[tex]y=8x-26[/tex]Answer: y = 8x - 26