Answer;
[tex]\text{Vertex = (2,7)}[/tex]Explanation;
Here, we want to get the vertex of the given quadratic equation
We have the vertex form as;
[tex]m(x)=a(x-h)^2+k[/tex]where the vertex is;
[tex](h,k)[/tex]The parameters of the parabola represents the coefficient of each individual unit
The coefficient of x^2 is 1
The coefficient of x is -4
The coefficient of the last number is 11
Now, we get the value of h as follows;
[tex]h\text{ = }\frac{-b}{2a}\text{ =}\frac{4}{2}\text{ = 2}[/tex]To get the value of k, we susbtitute the value of h for x
So, we have;
[tex]\begin{gathered} m(2)=2^2-4(2)+11 \\ m(2)=7 \end{gathered}[/tex]So, we have the value of k as 7
The vertex is thus a minimum at (2,7)
