Given the right triangle JKL
The hypotenuse of the triangle is the side JL
The given side KL = 17 m and represents the adjacent to the given angle 22
so,
[tex]\begin{gathered} \cos 22=\frac{adjacent}{hypotenuse} \\ \\ \cos 22=\frac{KL}{JL} \\ \\ \cos 22=\frac{17}{JL} \\ \\ JL=\frac{17}{\cos 22} \end{gathered}[/tex]
IT can be also calculated as following :
The other acute angle = 90 - 22 = 68
So, the opposite side of the angle 68 i
